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How does an open load error effect the operation of a PWM HS+LS output.

Kerry Brock 1 month ago in IQANdesign updated by Chris Litwin 1 month ago 1

I am testing logic with a MC43 and using a PWM HS+LS output.

In the system we are using both sides of the output (+ and -) to drive two individual devices.

Both should never operate at the same time.

To simulate one of the device not operating, we unplug one of the solenoids.

With logic, this automatically causes the other side of the output to now function.

Basically, if the + side fails, it should switch to the - side and operate.

We are getting an open load error on the output with one of the solenoids unplugged and it does not allow us to operate the other solenoid on the PWM HS+LS output.

Is the output designed to shut off both sides if one side detects open load or should the other side work if one side detects open load?

As an example:

Image 4494



If the solenoid between C2:67 and C2:15 is unplugged, but the solenoid between C2:67 and C2:31 is plugged in and fully operational, should we be able to command it with an input signal of -100?

I don't know about the software design, but in our systems both outputs will be disabled if one is unplugged.