0

MD5 video output

A DOMS 7 months ago • 0

Hi 

Is there a way to duplicate MD5 screen on an another standard screen ?

Throught an ethernet port for example ?

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Wireless can bus

Tuomas 8 months ago • updated by Lars Bolduc 7 months ago • 2

Has anyone tried this between Iqan masters, like MD5 <-> MC42?https://www.ifm.com/fi/en/shared/productnews/2023/hmi/canwireless-effective-local-m2m-dialogue

Or is there some other wireless CAN-bus adapter that works in Iqan?

0
Under review

MD4 goes blue screen and stops running

705David 10 months ago • updated by Gustav Widén (System support) 10 months ago • 1

We have an MD4-7 that's essentially just used for a displaying some camera feeds through ethernet.

We have multiple machines with this camera system and only one of them is experiencing the problem.

The MD4-7 will randomly crash and show a blue screen with an error code. 


I believe the code is "os_error (0x1000002) drv_CanInt"

The MD4 is running IQAN 7.05.

What does this error code mean?

Image 5165

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Math Channel Display issue

Leighton 10 months ago • updated 10 months ago • 4

I am hoping that this is not actually an issue and there is some setting I mis-clicked somewhere. However, I am having an issue with math channels not displaying correctly on a singular program.

It recently came to my attention that when I transitioned a program from IQAN 6.08 to IQAN 7.04 there has been a pair of Integer math channels that have been displaying 0 at all times. The odd part is that when I measure the program live with IQANDesign or IQANRun, both channels have numbers assigned which are correctly being passed elsewhere in the program, but the screen itself displays both as zero.

I have since attempted to assign flat numbers to the Integer math channels, or changing them into Normal Math Channels, adding math channels to different function groups, recreating the code in a different function group, and so on, however nothing I do changes the value displayed on screen to anything other than 0. I transitioned the 6 file to 7 over again, and it acts in the same odd manner, but when I compared the 6 program to the 7 the only detected changes were the expected date, Checksum, and Security changes that come with updating a program to 7.

The especially frustrating part is that when I start a blank program from scratch, all the math channels work and display as expected, and the same code displays correctly in a dozen other programs made in IQANDesign 7.04.

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P70 ON/OFF with direct 12V

Cam McCulloch 10 months ago • updated 10 months ago • 0

HI,

We have a P70CF with Proportional Coils. We only need to operate them electrically as on/off. Can this be done with direct 12V from a switch?

P70CF-03-08297 (2210640902)

Thanks,
Cam

0

I have a IQAN-MD3 with Erronious application 2A09

Doug Smith 12 months ago • updated 12 months ago • 2
0

No application Available

Todd F Reddick 12 months ago • updated by Thomas Moberg (System support) 12 months ago • 3

What causes blink code no application available? We shipped a programmed module to a customer. They get a blink code for no application available.  MC41

0

European Cyber Resilience Act

A DOMS 1 year ago • updated by Gustav Widén (System support) 4 weeks ago • 5

Are you working to correspond to the new European Cyber Resilience Act ?
It will be imposed by the Machinery Directive in 2027.

https://industrialcyber.co/expert/cra-and-machinery-regulation/

https://www.european-cyber-resilience-act.com/

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ID tag, termination resistor help

Mr. Blonde 1 year ago • updated by Pierre Fagrell 1 year ago • 11

I have an IQAN MD3, XS2 & XA2 set up in an excavator as part of a hydraulic attachment. The system is no longer supported by the OEM as they are no longer in business. I’m in need of some resistors and one of them is proving to be difficult to find.

The resistor is marked 1T and according to the Parker literature there are four versions of this resistor and it seems the connection ends are the difference between them. So my thought is I can use any Parker 1T resistor and just solder it in.


Am I correct in my thinking? Thanks in advance.


Chris